Let's get straight to the point!
A 5000VA pump at a voltage of 160 Volts will spend how much more electricity if it operates for 100 hours in a row than at 220 Volts, the solution to the problem, the price of 1 kilowatt costs 10 cents
To solve this problem, we can use the formula:
Energy (in kWh)=(Power (in Watts)Voltage (in Volts))×Time (in hours)Energy (in kWh)=(Voltage (in Volts)Power (in Watts))×Time (in hours)
Where:
- Power = 5000 VA (volt-amperes),
- Voltage1 = 160 Volts,
- Voltage2 = 220 Volts,
- Time = 100 hours.
First, let's calculate the energy consumption for both cases:
-
At 160 Volts: Energy1=(5000160)×100Energy1=(1605000)×100
-
At 220 Volts: Energy2=(5000220)×100Energy2=(2205000)×100
Now, let's find the difference in energy consumption:
Difference in Energy=Energy1−Energy2Difference in Energy=Energy1−Energy2
Next, we'll calculate the cost difference using the given price of 1 kilowatt-hour (0.10 dollars):
Cost Difference=Difference in Energy×Cost per kWhCost Difference=Difference in Energy×Cost per kWh
Now, let's perform the calculations:
-
Energy at 160 Volts: Energy1=(5000160)×100≈3125 kWhEnergy1=(1605000)×100≈3125kWh
-
Energy at 220 Volts: Energy2=(5000220)×100≈2272.73 kWhEnergy2=(2205000)×100≈2272.73kWh
Now, find the difference in energy consumption: Difference in Energy=3125−2272.73≈852.27 kWhDifference in Energy=3125−2272.73≈852.27kWh
Now, calculate the cost difference: Cost Difference=852.27×0.10≈85.23 dollarsCost Difference=852.27×0.10≈85.23dollars
Therefore, if the pump operates for 100 hours continuously, it will spend approximately 85.23 dollars more electricity at 160 Volts compared to 220 Volts.
85 USD DOLLARS!!!